0=x^2-41x+200

Solution for 0=x^2-41x+200 equation:

0=x^2-41x+200

We move all terms to the left:

0-(x^2-41x+200)=0

We add all the numbers together, and all the variables

-(x^2-41x+200)=0

We get rid of parentheses

-x^2+41x-200=0

We add all the numbers together, and all the variables

-1x^2+41x-200=0

a = -1; b = 41; c = -200;
Δ = b2-4ac
Δ = 412-4·(-1)·(-200)
Δ = 881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{881}}{2*-1}=\frac{-41-\sqrt{881}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{881}}{2*-1}=\frac{-41+\sqrt{881}}{-2}
$